Question

Please answer these questions, urgent, please do not spam, step by step plz don't spam please answer ​

Answer 1

Answer:

Sorry but I don't know how to solve 3 and 4 the second part

Step-by-step explanation:

$2)x + \frac{1}{x} = 5 \\ squaring \: on \: both \: the \: sides \\ {(x + \frac{1}{x}) }^{2} = {(5)}^{2} \\ {(x)}^{2} + 2(x)( \frac{1}{x} ) + { (\frac{1}{x}) }^{2} = 25 \\ {x}^{2} + 2 + \frac{1}{ {x}^{2} } = 25 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 25 - 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 23 \\ sqaring \: on \: both \: the \: sides \\ {( {x}^{2} + \frac{1}{ {x}^{2} } )}^{2} = {(23)}^{2} \\ {( {x}^{2}) }^{2} + 2( {x}^{2} )( \frac{1}{ {x}^{2} } ) + { (\frac{1}{ {x}^{2} } )}^{2} = 529 \\ {x}^{4} + 2 + \frac{1}{ {x}^{4} } = 529 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 529 - 2 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 527 \\ 4)x + y = 5 \\ squaring \: on \: both \: the \: sides \\ {(x + y)}^{2} = {(5)}^{2} \\ {x}^{2} + {y}^{2} + 2xy = 25 \\ {x}^{2} + {y }^{2} + 2(6) = 25 \\ {x}^{2} + {y}^{2} + 12 = 25 \\ {x}^{2} + {y}^{2} = 25 - 12 \\ {x}^{2} + {y}^{2} = 13$