Math, asked by gowthamikeerthana, 5 months ago

please answer these two questions please please please ✍✍​

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Answers

Answered by yamunachembolu
1

Answer:

Hope this will help you

formula's used in the above questions

are

1.sin^2A+cos^2A=1

2.sec^2A-tan^2A=1

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Answered by keerthi2711
0

Answer:

3 question answer is

Step-by-step explanation:

sin^4A- cos^4A= (sin^2A+ cos^2A)*(sin^2A- cos^2A)

= 1*(sin^2A-(1-sin^2A))

= 2sin^2A-1

2 question answer is

√1- sin theta. √1-sin theta*√1-sin theta

......................... =. ..................................................

√1+sin theta. √1+sin theta*√1-sin theta

√(1- sin theta)^2

= ..............................

√ cos^2 theta

root and square will cancelled

finally,

√1-sin theta. 1 sin theta

............................. =. .................... - .......................

√1+sin theta. cos theta. cos theta

= sec theta - tan theta

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