Question

please answer this.....​

Answer 1

Answer:

(i) Compound with vinegar like smell is acetic acid (X) which in the presence of few drops of sulphuric acid (Z) reacts with ethanol and gives an ester as:

{ C }_{ 2 }{ H }_{ 5 }OH+C{ H }_{ 3 }COOH\quad (X)\overset { { (Z)H }_{ 2 }S{ O }_{ 4 } }{ \rightarrow } { C{ H }_{ 3 }COO{ C }_{ 2 }{ H }_{ 5 } }(Y)+{ H }_{ 2 }OC

2

H

5

OH+CH

3

COOH(X)

→

(Z)H

2

SO

4

CH

3

COOC

2

H

5

(Y)+H

2

O

(ii)Structure of X is:

H-\overset { \underset { | }{ H } }{ \underset { \underset { H }{ | } }{ C } } -\overset { \overset { O }{ || } }{ \underset { \underset { OH }{ | } }{ C } }H−

H

∣

C

∣

H

−

OH

∣

C

∣∣

O

(iii) Reaction is esterification of acid.

Answer 2

Answer:

(1) compound X is ethanoic acid.

compound Y is ethyl ethanoate ester.

compound Z is sulphuric acid.

(2) structural formula of X

 CH3--COOH

(3)this reaction is called esterification reaction.