Question

Please answer this!!

Answer 1

Answer:

4th term of the expansion

$= \binom{7}{3} ( \frac{x}{2} )^{7 - 3}y ^{3} \\ = 35( \frac{x}{2}) ^{4} {y}^{3} \\ = 35 \times \frac{ {x}^{4} }{16} \times y^{3} \\ = \frac{35}{16} {x}^{4} {y}^{3}$