Question

please answer this...​

Answer 1

$\bold{\huge{\underline{\underline\red{ANSWER: }}}}$

$\vec{A} \: = \hat{\imath}+2\hat{\jmath}+3\hat{k}$

Multiplying the vector by 2

$2(\vec{A} )\: = 2(\hat{\imath} )+2(2\hat{\jmath} )+2(3\hat{k})$

$= 2\vec{A} \: = 2\hat{\imath}+4\hat{\jmath}+6\hat{k}$

Magnitude of a vector $\vec{A} \: = x\hat{\imath}+y\hat{\jmath}+z\hat{k}$ = $\sqrt{ {x}^{2} + {y}^{2} + {z}^{2} }$

Magnitude of $2\vec{A} \: = 2\hat{\imath}+4\hat{\jmath} +6\hat{k}$ =

$\sqrt{ {2}^{2} + {4}^{2} + {6}^{2} }$

$= \sqrt{4 + 16 + 36}$ $= \sqrt{56}$

$= \sqrt{4 \times 14}$ $= 2 \sqrt{14}$

ADDITIONAL INFORMATION :-

$\longrightarrow$ Vector is a quantity that requires both magnitude and direction.

$\longrightarrow$If a vector is displaced parallel to itself the value of vector does not change.

$\longrightarrow$Resultant Vector of two vectors = $\sqrt{ {A}^{2} + {B}^{2} + 2 AB COS\theta}$

$\longrightarrow$Multiplaction of a vector by a algebraic

= $m\vec{A} \: = m\hat{\imath}+m\hat{\jmath}+m\hat{k}$

$\bold{\huge{\underline{\underline\red{THANKS}}}}$