please answer this....... ......................
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The weight of hanging part (L/3)of chain is (1/3mg).this weight acts at centre of gravity of the hanging part,which is at a distance of (L/6)from the table.
As work done=force×distance
therefore,W=Mg/3×L/6=MgL/18...
i think this is the answer??
hope it helps.....
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