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first find angle b= 52+90+x=180
142+x=180
x=180-142
x=38
BE is the bisector of b
38/2=19
In triangle BOD
ODB=90
OBD=19
90+19+x=180
109+x=180
x=71
BOD=71
in triangle AEB
90+19+x=180
109+x=180
x=71
AEO=71
pls mark brainliest
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Answer:
∠BOD =71°
∠AEO=64°
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