please answer this 25th question ASAP.
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Step-by-step explanation:
sinA-cosA+1/sinA+cosA-1
devide by cosA in each term
=tanA+secA-1/tanA-secA+1
={(tanA+secA)-1}(tanA-secA)/(tanA-secA+1)(tanA-secA)
=tan²A-sec²A-tanA+secA/(tanA-secA+1)(tanA-secA)
=-1-tanA+secA/(tanA-secA+1)(tanA-secA)
=-1/tanA-secA
=1/secA-tanA
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