Math, asked by priyankasharmaujn, 2 months ago

Please Answer This
3x²-41x+60=0​

Answers

Answered by Athul4152
1

==> [-(-41) +/- √(41^2 - 4 ×3×60)] / 2×3

==>. 41 +/- √(1681 - 720 ) / 6

==>. 41 +/- √(961) / 6

==> 41 +/- 31 / 6

==> 41 + 31 / 6. ==> 41-31 /6

= 12. = 5/3

Answered by misscutie94
16

Answer:

Question :-

  • 3x² - 41x + 60 = 0

Answer :-

➠ 3x² - 41x + 60 = 0

➻ 3x² - (36 + 5)x + 60 = 0

➻ 3x² - 36x - 5x + 60 = 0

➻ 3x(x - 12) - 5(x - 12) = 0

➻ (x - 12) (3x - 5) = 0

➻ (x - 12) = 0

➻ x - 12 = 0

➻ x = 12

➻ (3x - 5) = 0

➻ 3x - 5 = 0

➻ 3x = 5

➻ x = 5/3

∴ The value of x is 12, 5/3

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