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x = 85° ( alternate angles) SO is a transversal
130° + y =180° ( supplementary angles)
so, y = 50°
so, x + y = 85°+50°=135°
130° + y =180° ( supplementary angles)
so, y = 50°
so, x + y = 85°+50°=135°
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at q there must be angle of 180deg.
so the sum of angles at q will be 180
1st angle is 130 the other angle must be 50deg
so y=50
and x=85 as because of opposite alternate angle
therefore sum of x+y=50+85=135
so the sum of angles at q will be 180
1st angle is 130 the other angle must be 50deg
so y=50
and x=85 as because of opposite alternate angle
therefore sum of x+y=50+85=135
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