please ANSWER THIS ASAP
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Let P(X) =
Let G(X) = (X²-3X+2) = (X²-2X-X+2)
=> X(X-2) -1(X-2)
=> (X-2) (X-1).
Now, P(X) will be exactly divisible by G(X) if it is exactly divisible by (X-2) as well as (X-1).
Putting X = 2 in P(X).
P(X) =
P(2) = ( 3 × 23 - 8 × 22 + 3 × 2 + 2)
=> (24-32+6+2) = (24-24) = 0
And,
P(1) = (3 × 13 -8 × 12 + 3 × 1 +2)
=> (3-8+3+2) = (5-5) = 0
Therefore,
P(X) is exactly divisible by (X-2) and (X-1)
So , P(X) is exactly divisible by (X²-3X+2)
Hence,
P(X) is exactly divisible by (X²-3X+2)
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