Question

Please answer this
both

Answer 1

When potassium iodide is added to a solution of lead nitrate a precipitate of lead iodide and solution of potassium nitrate is formed

KI+Pb(NO3)2—>PbI2+KNO3


The reducing agent used in reduction of CuO is H2

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Answer 2

HI FRIEND,
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1) When potassium iodide is dissolved in lead nitrate a yellow precipitate is observed. This yellow precipitate is lead iodide. Along with this potassium nitrate is also formed. This is a double displacement reaction. Equation:

Pb(NO3)2 + KI → PbI2 + KNO3

2) The reducing agent used in copper oxide is hydrogen.

CuO + H2 → Cu + H2O
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