Math, asked by fmalik4, 10 months ago

Please answer this correctly

Attachments:

Answers

Answered by tennetiraj86
1

Step-by-step explanation:

here the given figure shows a sector but I solved it standard method

Attachments:
Answered by EuphoricEpitome
3

Answer:

Answer:

» Given:

\small\mathbb\fcolorbox{black}{pink}{Perimeter\:of \:the \:figure\:is \: 14.28 \:km}

» Perimeter of figure will be -

r+r+ 2πr/4

= 2r+ πr/2

by equating with the value..

(using π = 3.14)

2r + 3.14r/2 = 14.28

2r + 1.57r = 14.28

3.57 r = 14.28

r = 14.28/3.57

\pink{r = 4 km}

» We know that,

\pink{Area\:of \:quadrant =} πr²/4

by putting values

πr²/4 =

(3.14×4)/4

= 3.14

therefore,

\blue{Area\:of\:the\:figure= 3.14\: km\: squared }

Similar questions