Question

Please answer this correctly

Answer 1

Answer:

» Given:

$\small\mathbb\fcolorbox{black}{pink}{Perimeter\:of \:the \:figure\:is \: 14.28 \:ft}$

» Perimeter of figure will be -

r+r+ 2πr/4

= 2r+ πr/2

by equating with the value..

(using π = 3.14)

2r + 3.14r/2 = 14.28

2r + 1.57r = 14.28

3.57 r = 14.28

r = 14.28/3.57

$\pink{r = 4 ft}$

» We know that,

$\pink{Area\:of \:quadrant =}$ πr²/4

by putting values

πr²/4 =

(3.14×4)/4

= 3.14

therefore,

$\blue{Area\:of\:the\:figure= 3.14\: ft\: squared }$

Answer 2

$\huge\underline\mathrm{Question:-}$

• To find quarter circle's area.

$\huge\underline\mathrm{Given:-}$

• Perimeter of quarter circle is 14.28 ft.

$\huge\underline\mathrm{Solution:-}$

★ Perimeter of fig will be :

• 2r + pie r / 2

Putting values according to conditions ...

$14.28 = 2r + \frac{3.14r}{2}$

$14.28 = 2r + 1.5r$

$14.28 = 3.5r$

$\frac{14.28}{3.5} = r$

$4 = r$

$r = 4ft$

★ Area of Quadrant :

$\frac{\pi {r}^{2} }{4}$

$\frac{3.14 \times 16}{4}$

$= 3.14$

$\huge\underline\mathrm{Answer:-}$

• The area of quarter circle is 3.14 sq.ft