Question

.What is the largest 3-digit number that divides by 24 divided by 7. left and 36 divided by 19 left?​

Answer 1

Answer:

What is the greatest number of 3 digits which when divided by 6, 9, and 12 leaves a remainder of 3 in each case?

Flexible support where it's needed.

I wrote down all the multiples for 6, 9, and 12. The least common multiple was 36.

6 12 , 18, 24 , 30, 36, 42, 48, 54, 60, 66, 72

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108

12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132,

What is the largest 3 digit number divisible by 36

999 /36 =24 remainder 35

You need a number with r of 3

35–24 = 11

999 - 11 = 988

988/ 36 = 2 7 r 4

980/36 = 27 r 2

972/36 = 27 r 3

The number must be 972+3 = 975

You can check this by dividing 975 by

6, 9, 12.