Question

please answer this early

Answer 1

heya

given here .

tan¢=1-a^2.-------1)

and it must be tan¢=√1-a^2-------2)

from lhs .

sec¢+tan^3¢*cosec¢

now,, sec¢+tan^2¢*tan¢*cosec¢

=)sec¢+1-a^2(tan¢)*cosec¢------from 1)

=)1/cos¢+1-a^2(sin,¢/cos¢*1/sin¢)

=)1/cos¢+1-a^2*1/cos¢

tan¢+1-a^2tan¢ 【multiplying by sin¢】

√1-a^2+(1-a^2)(√1-a^2)

=)√1-a^2+(1-a^2)*√1-a^2) Rhs

hope it help you..

@rajukumar☺