Question

Please answer this everyone.

Answer 1

Heya... I think this can be ur answer dear!!

CosA=2/5
Sec A=5/2

Now,
4+4tan2 =4(1+tan2) = 4*sec2A
=4(5/2)2
=4*25/4 =25

Hope it helps you dear ☺️☺️and all the best for exams

Answer 2

Given Cot A = 2/5.

We know that secA = $\frac{1}{cosA}$

                                  = $\frac{1}{ \frac{2}{5} }$

                                  $= \frac{5}{2}$


We know that tan^2A + 1 = sec^2A.

It can be written as $tan^2A = sec^2A - 1$

                                 $tan^2A = ( \frac{5}{2} )^2 - 1$

                                 $tan^2A = \frac{25}{4} - 1$

                                 $tan^2A = \frac{25 - 4}{4}$

                                 $tan^2A = \frac{21}{4}$


Given:


4 + 4 tan^2A = $4 + 4( \frac{21}{4})$

                       = 4 + 21

                       = 25



Hope this helps!