Question

please answer this fast​

Answer 1

Answer:

h.c.f. Of 20 & 16

2 20,16

2 10, 8

2 5, 4

2 5, 2

2 5, 1

5 1, 1

therefore H.C.F is 2×2=4m

Maximum length of ropes is 4m

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Answer 2

Answer:

HCF of 16&20

16=2*2*2*2

20=2*2*5

so HCF=2²=4

so length of each piece =4cm & we will have 9 such pieces