Question

please answer this fast ​

Answer 1

Given:

• A linear equⁿ is given to us.
• The equⁿ is 5x + 3y = 10.

To Find:

• The point at which it meets at x - axis.

Answer:

At x - axis we know that y - coordinate / ordinate will be 0 . So on substituting y = 0 , in the above equⁿ , we can easily find the x-coordinate/abssicca at which the line will cut x - axis .

⇒ 5x + 3y = 10.

⇒ 5x + 3×0 = 10.

⇒ 5x + 0 = 10.

⇒ 5x = 10.

⇒ x = 10/5.

⇒ x = 2.

Hence the coordinate of x is 2 .

So the point will be (2,0). [d].

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Let us also see at which point will the graph cuts y - axis .For this we will substitute x = 0 , in the above equⁿ since at y - axis value of abssicca / x - coordinate is 0.

⇒ 5x + 3y = 10.

⇒ 5×0 + 3y = 10.

⇒ 0 + 3y = 10.

⇒ 3y = 10.

⇒y = 10/3.

⇒ y = 3.33 .

Hence the coordinate of y / ordinate is 3.33

So the line will cut y-axis somewhere at (0,3.33).

[For better understanding also refer to graph in the attachment : ]