Question

PLEASE...ANSWER THIS FAST AND CORRECTLY.. Calculate percentage composition of methanol (CH3OH)

Answer 1

Answer:

mass of methanol: 12 + 3 + 16 + 1 = 32

mass of carbon = 12

mass of oxygen = 16

mass of hydrogen = 4

%composition:

% of Carbon = (12/32)*100% = 37.5%

% of oxygen = (16/32)*100% = 50%

% of hydrogen = (4/32)*100% = 12.5%