Question

Please answer this fast friends

Answer 1

If A^-1 exists that means the determinant cannot be zero
So we take determinant
2(6-5)-lambda(0-5)+(-3)[0-2]
2+5lambda+6
5lambda+8
Now to find for which it exists we need to find for which it doesn't so equate it to zero
5lambda+8=0
5lambda=-8
lambda=-8/5
So the answer is that A^-1 exists for all values except lambda=-8/5
HOPE IT HELPS
MARK AS BRAINLIEST