Math, asked by smrativerma2006, 6 months ago

please answer this fast i have assignments tomorrow plz fast and with full explanation of the question​

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Answered by gagandeepkundi
3

Answer:

66 days

Step-by-step explanation:

Let us assume that one soldier eats 'n' units of food in a day.

Then, 330 soldiers will eat 330 x n times per day.

330 soldiers in 90 days will eat = 330 soldiers x 90 days x n = 29,700 n units of food

Total Food left after 20 days= 29700 n - (330 x 20 x n)

                                               = 23,100 n

Now, for next 70 days there are 20 more soldiers i.e. 330+20=350 solders

Amount of food these soldiers will eat in a day = 350 n

Number of days the food will last = 23,100 n / 350 n = 66 days

Answered by tyrbylent
0

Answer:

66 days

Step-by-step explanation:

Amount of food is (330×90) soldier-days

In 20 days amount of food left is (330×70) soldier-days

Amount of food will be served is (350)×(x) soldiers-days

350x = 23,100 ⇒ x = 66 days

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