Question

Please answer this
find the value of sin60°+tan45°-cos30°
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Answer 1

$sin60 = \frac{ \sqrt{3} }{2}$

tan 45° = 1

$\cos(30) = \frac{ \sqrt{3} }{2}$

sin 60° + tan 45° - cos 30°

$\frac{ \sqrt{3} }{2} + 1 - \frac{ \sqrt{3} }{2} = 1$

Answer 2

Answer:

$\frac{ \sqrt{3} }{2} + 1 - \frac{ \sqrt{3} }{2} \\ \frac{ \sqrt{3 + 2 - \sqrt{3} } }{2 } \\ = \frac{2}{2} \\ = 1 \: ans \:$

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