Please answer this Friends . send me reply as photo
Attachments:
Answers
Answered by
0
. In the figure, POQ is a line. Ray
OR is perpendicular to line PQ. OS
is another ray lying between rays
OP and OR. Prove that
∠ROS = 1
2 (∠QOS – ∠ POS)
Sol. ∠ROS = ∠ROP – ∠POS …(1)
and ∠ROS = ∠QOS – ∠QOR …(2)
Adding (1) and (2),
∠ROS + ∠ROS = ∠QOS – ∠QOR
+ ∠ROP – ∠POS
⇒ 2∠ROS = ∠QOS – ∠POS (∵ ∠QOR = ∠ROP = 90°)
⇒ ∠ROS = 1
2 (∠QOS – ∠POS) Proved
Similar questions