Math, asked by tulu1, 1 year ago

please answer this.i promise to mark the 1st correct answer as brainlist answer. please urgent

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Answered by Immaman507

1

Sin3x dx=[1/3cos3x]^30°-0°
Integral limit 0°-30°sin3x=[1/3cos30°-13cos0°]
Integral limit 0°-3.°SIN3x=-1/3

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