Question

please answer this

i will mark as brain list​

Answer 1

$given ,</p><p> \: p(y) = 5y {}^{2} - 7y + 1 \\ a = 5 ,\: b = - 7, \: c = 1 \\ we \: know \: that, \: \\ \: \: \: sum \: of \: zeros \: = \frac{ - b}{a} \\ \: \: \alpha + \beta = \frac{7}{5} \\ \: \: products \: of \: zeros = \frac{c}{a} \\ \alpha \beta = \frac{1}{5} \\ now ,\: \\ \: \: \: \: \: \frac{1}{ \alpha } + \frac{1}{ \beta } \\ \frac{ \beta + \alpha }{ \beta \alpha } \\ = \frac{7}{5} \div \frac{1}{5} \\ = \frac{7}{5} \times 5 \\ = 7</p><p> </p><p></p><p></p><p>$