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sin=a/b+c
cos^2= 1- a^2/(b+c)^2
={ (b+c)^2- a^2}/(b+c)^2
cos= √{( b+c)^2-a^2}/(b+c)^2
=1/b+c√[{(b+c)^2-a^2}×4bc/4bc]
=2√bc/(b+c). cosA/2
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here is your answer please Mark brainliest
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