Question

Please answer this immediately and also give working!
If you do it correctly I will follow you
If wrong I will report you

Answer 1

Answer:

q5:-

let the 1st angle be 4x and second be 5x

4x+5x =180 (sum of co-interior angle of parallelogram)

9x=180

x=20

first angle is 4x =4*20=80°

second ange is 5x=5*20=100°

3rd angle = 1st angle and 2nd angle= 4th angle (opposite angle of parallelogram are equal)

so 3rd angle is 80°

and 4th angle is 100°

q6:-

let 1st side be x and 2nd be 5x

1st side is equal to 3rd side and 2nd side is equal to 4th side

so 3rd side is x

and 2nd side is 5x

x + x + 5x+ 5x = 240

12x =240

x=20

side 1 and 3 are 20cm

and 4th and 2nd = 5x=5*20=100cm

q7:-

sum of a pair of opp. angle =300(given)

let the both remaining angle be x

x+x+300 =360°

2x + 300=360

2x =360-300

2x=60

x=30

sum of both remaining angles =2x=60°

q8:-

3x+4=5x-2(opposite angles of parallelogram are equal)

4+2 =5x-3x

6=2x

x=6/2

x=3

so 1st angle = 3*3+4= 13

2nd angel + 1st angle =180°(sum of co- interior angles )

2nd angle =180-13= 167*

3rd angle = 1st angle =13°( opposite angles of parallelogram are equal)

4th angle = 2nd angle =167°( opposite angles of parallelogram are equal)

now you can brainiest my answer