Question

Please answer this math question asap!! 30 points and brainliest!!
BRAINLIEST ONLY IF YOU SHOW YOUR WORK!

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Cost\:of\:water\:required=\ \:104.125}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Lenght \: of \: pool = 12 \: ft \\ \\ \tt: \implies Breadth\: of \: pool = 12 \: ft \\ \\ \tt: \implies Height \: of \: pool = 6 \: ft \\ \\ \tt: \implies Cost \: of \: {1 \: m}^{3} \: water = \ \: 4.25 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Cost \: to \: fill \: the \: pool \: with \: water = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Volume \: of \: pool = l \times b \times h \\ \\ \tt: \implies Volume \: of \: pool = 12 \times 12 \times 6 \\ \\ \tt: \implies Volume \: of \: pool = 144 \times 6 \\ \\ \tt: \implies Volume \: of \: pool = 864 \: {ft}^{3} \\ \\ \tt: \implies Volume \: of \: pool = 864 \times 0.0283 \\ \\ \green{\tt: \implies Volume \: of \: pool \approx 24.5 \: {m}^{3}} \\ \\ \bold{For \: finding \: cost} \\ \tt: \implies Cost \: of \: 1 \: {m}^{3} = \ \: 4.25 \\ \\ \tt: \implies Cost \: of \: 24.5 \: {m}^{3} \: water = 4.25 \times 24.5 \\ \\ \green{\tt: \implies Cost \: of \: 24.5 \: {m}^{3} \: water =\ \: 104.125}$

Answer 2

Answer:

$\bigstar\:\boxed{\sf 1\:foot=0.305\:metre}$

◗ Length = 12 × 0.305 = 3.66 metre

◗ Breadth = 12 × 0.305 = 3.66 metre

◗ Height = 6 × 0.305 = 1.83 metre

$\rule{200}{1}$

$\underline{\bigstar\:\textsf{According to the Question :}}$

$:\implies\tt Cost = Volume \times Rate\\\\\\:\implies\tt Cost = (l \times b \times h) \times Rate\\\\\\:\implies\tt Cost = (3.66m \times 3.66m \times 1.83m) \times \ \:4.25 \:m^{-3}\\\\\\:\implies\tt Cost =24.513948\:\cancel{m^{3}} \times \ \:4.25 \: \cancel{m^{-3}}\\\\\\:\implies\tt Cost = 24.513948 \times \ \:4.25\\\\\\:\implies\underline{\boxed{\tt Cost =\ \: 104.18}}$

⠀

$\therefore\:\underline{\textsf{Cost to fill the pool will be \textbf{\ 104.18}.}}$