Question

Please answer this math question asap!! 30 points and brainliest!!
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Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\angle B\approx47.9\degree}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Length \: of \:AB= 55\:ft\\ \\ \tt: \implies Length \: of \: BC= 37\:ft\\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies \angle B= ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Cos \: \theta = \frac{Base}{Hypotenuse} \\ \\ \tt: \implies Cos \: B = \frac{BC}{AB} \\ \\ \tt: \implies Cos\: B= \frac{37}{55} \\ \\ \tt: \implies Cos \: B= 0.67 \\ \\ \tt: \implies Cos \: B= Cos \:47.93 \\ \\ \green{\tt: \implies \angle B \approx 47.9 \degree}\\ \\ \purple{\bold{Some \: extra \: information}} \\ \pink{\tt{\circ \: Sin \: \theta = \frac{p}{h} }} \\ \\ \pink{\tt{\circ \: Cos \: \theta = \frac{b}{h} }} \\ \\ \pink{\tt{\circ \: Cot \: \theta = \frac{b}{p} }} \\ \\ \pink{\tt{\circ \: Cosec \: \theta = \frac{h}{p} }} \\ \\ \pink{\tt{\circ \: Sec \: \theta = \frac{h}{b} }} \\ \\ \pink{\tt\circ \: {Sin}^{2} \theta + Cos^{2} = 1}$

Answer 2

$</p><p>\tt{\huge {\pink{Hello!!!}}}$

$\huge{\fbox{\fbox{\rightarrow{\mathfrak {\green{Question \: - }}}}}}$

• A 55 ft guy wire helps to support a tower.

• The wire is anchored to the ground 37 ft from above the base of the tower.

• What is the measure of the angle formed between the wire and the ground to the nearest degree?

$\huge{\fbox{\fbox{\rightarrow{\mathfrak {\purple{Answer \: - }}}}}}$

Answer:

$\green{\tt{\therefore{\angle B\approx47.9\degree }}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}}$

$</p><p>\red{\tt{ Length \: of \:AB= 55\:ft\\ \\ \tt: \implies Length \: of \: BC= 37\:ft }}}$

$\red{\underline \bold{To \: Find:}}$

Given:

:⟹ Length of AB = 55ft.

:⟹Length of BC = 37ft.

To Find:

:⟹∠B=?

• According to given question :

As we know that :

$</p><p>\tt{\red{Cos ( \phi ) = \frac{Base}{Hypotenuse} = \frac{AB}{AC} = \frac{55}{57 } = 0.67 }}}$

:⟹Cos47.93

:⟹∠B≈47.9°