Question

Please answer this only who knows.... ​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{5 } + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \\ = \frac{ \sqrt{5 } + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5 } + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } \\ = \frac{ (\sqrt{5 } + \sqrt{3}) {}^{2} }{ ( { \sqrt{5} )}^{2} - (\sqrt{3}) {}^{2} } \\ = \frac{( { \sqrt{5} })^{2} + ({ \sqrt{3} )}^{2} + 2 \times \sqrt{5 } \times \sqrt{3} }{5 - 3} \\ = \frac{5 + 3 +2 \sqrt{15} }{2} \\ = \frac{8 + 2 \sqrt{15} }{2} \\ = \frac{2(4 + \sqrt{15}) }{2} \\ = 4 + \sqrt{15}$

$a + b \sqrt{15} = 4 + \sqrt{15}$

a = 4

b√15=√15

b= 1