Question

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Answer 1

Answer:

given that the base of triangle is 9/4 times of its height . And area is 144 cm² . Let the height be h , then its base be 9h/4

• according to the question

area(Δ) =

$\frac{base \times height}{2}$

$144 {cm}^{2} = \frac{9h \times h}{4 \times 2}$

${h}^{2} = \frac{12 \times 12 \times 2 \times 2}{3 \times 3}$

$h = \sqrt[]{ \frac{12 \times 12 \times 2 \times 2}{3 \times 3} }$

$h = \frac{(12)(2)}{3}$

$h = 8cm$

therefore

• height = 8 CM
• base = 9h/4 =18 CM

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