Question

please answer this please

the answer is - a apply method here
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Answer 1

Given:

(x + b)/(a - b) = (x - b)/(a + b)

=> (x + b)(a + b) = (x - b)(a - b)

=> xa + xb + ab + b^2 = xa - bx - ba + b^2

=> xa + xb + ab + b^2 - xa + bx + ba - b^2

=> 2xb + 2ab = 0

=> 2b(x + a) = 0

=> x + a = 0

=> x = -a.

Hope it help!

Answer 2

Answer:

x+b/a-b=x-b/a+b

Step-by-step explanation:

solution :- x+b/a-b=x-b/a+b

=> (a+b)(x+b)=(a-b)(x-b)

=> ax+ab+bx+b²=ax-ab-bx+b²

=> ax-ax+ab+ab+bx+bx=b²-b²

=> 2ab+2bx=0

=> 2b(a+x)=0