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prove that triangles ABD and FEC are congruent by SAS property..... Then both AD=FC because these are corresponding parts of congruent triangles
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Given, AB= EF and BC=DE
B= 90°= E
By using Pythagoras theorem,
In triangle ABD,
AB^2+BC^2=AD^2
And in triangle DEC,
DE^2+EF^2= FC^2
AB^2+BC^2= FC^2
Since AB=EF and DE=BC
Therefore,
FC^2=AD^2
AD=FC
Hence proved.
B= 90°= E
By using Pythagoras theorem,
In triangle ABD,
AB^2+BC^2=AD^2
And in triangle DEC,
DE^2+EF^2= FC^2
AB^2+BC^2= FC^2
Since AB=EF and DE=BC
Therefore,
FC^2=AD^2
AD=FC
Hence proved.
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