Math, asked by human47, 1 year ago

. Please answer this problem i will mark u the brainliest if u answer me please it is urgent

Attachments:

originaljustice: 4000 tiles
human47: how
kv1431: yaar lets 1st room area as A1 and no. of tiles as n1., similarly for 2nd room A2 and n2 then directly (A1/n1) = (A2/n2)., apply this here A1 = 24, A2=96, n1 = 1000, then substitute you will get n2 ie., 2nd room's tiles

Answers

Answered by siddhartharao77
4

Given, length of the room = 6 m.

Given, breadth of the room = 4 m.

We know that Area of room = length * breadth

                                               = 6 * 4

                                               = 24 m^2.



Given, length of hall = 12 m.

Given, breadth of hall = 8 m.

We know that Area of hall = length * breadth

                                            = 12 * 8

                                            = 96 m^2.



Now,

Given that 24 m^2 = 1000 tiles.

Then, 1 m^2 =  1000/24

96 m^2 = (1000/24) * 96

             = 4000 .




Therefore, the number of tiles required = 4000.



Hope this helps!


human47: thanks for the help sir
siddhartharao77: Welcome!
Answered by BrainlyKing5
1
HEY MATE HERE IS UR ANSWER


FOR ROOM OF 6M AND 4M WE NEED 1000 TILES


THE AREA OF THAT ROOM IS = 6 X 4 = 24 M^2


THERE FOR IN 24 M^2 WE NEED 1000 TILES


SO IN SECOND ROOM WHOSE AREA = 12 X 8 = 96 M ^2


WE NEED NO OF TILES = 96/24 X 1000 = 4000 TILES


HOPE IT HELPS IF YES MARK AS BRAINLIEST

human47: thanks for the help bro
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