Question

please answer this que ​

Answer 1

F=a*x+bt^2 assume " * " as root

say,F=a*x =>1

dimension of F=> MLT^-2

dimension of a*x =>a.L^1/2

say,F=bt^2 =>2

dimension of F=MLT^-2

dimension of bt^2=b.T^2

eq.1 dimension-> MLT^-2=a.L^1/2

a=MLT^-2÷L^1/2

a=ML^1/2T^-2 =>3

eq.2 dimension->MLT^-2=b.T^2

b=MLT^-2÷T^2

b=MLT^-4 =>4

eq.3/4

a/b= ML^1/2T^-2÷MLT^-4

☆a/b= M^0L^-1/2T^2

Answer 2

Answer:

F=a*x+bt^2 assume " * " as root

say,F=a*x =>1

dimension of F=> MLT^-2

dimension of a*x =>a.L^1/2

say,F=bt^2 =>2

dimension of F=MLT^-2

dimension of bt^2=b.T^2

eq.1 dimension-> MLT^-2=a.L^1/2

a=MLT^-2÷L^1/2

a=ML^1/2T^-2 =>3

eq.2 dimension->MLT^-2=b.T^2

b=MLT^-2÷T^2

b=MLT^-4 =>4

eq.3/4

a/b= ML^1/2T^-2÷MLT^-4

☆a/b= M^0L^-1/2T^2

Step-by-step explanation: