Question

Please answer this question

Answer 1

B) 3/5......

KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2

KMnO4 = 5 electrons

ferrous oxalate in acidic solution = 3 electrons

while reaction exchange of electrons takes place..........so

3 moles of KMnO4 = 5 moles of FeC2O4

5 moles of FeC2O4 = 3 moles of KMnO4

so 1 mole of FeC2O4 = 3/5 moles of KMnO4

hence 3/5 moles of KMnO4 of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....

Hope you have got it