please answer this question 13th and 14th
Attachments:
Answers
Answered by
1
you can use Pythagoras theorem
Answered by
0
let a=35 , b=54 and c= 61
semi perimeter ,s=a+b+c÷2
=35+54+61÷2
=150÷2
=75
so, by heron's formula
area of the triangle=√s(s-a)(s-b)(s-c)
=√75(75-35)(75-54)(75-61)
=√75×40×21×14
=√3×5×5×2×4×5×7×3×7×2
=√3×3×5×5×5×2×2×7×7×4
=3×5×2×7√5×4
=210√20
semi perimeter ,s=a+b+c÷2
=35+54+61÷2
=150÷2
=75
so, by heron's formula
area of the triangle=√s(s-a)(s-b)(s-c)
=√75(75-35)(75-54)(75-61)
=√75×40×21×14
=√3×5×5×2×4×5×7×3×7×2
=√3×3×5×5×5×2×2×7×7×4
=3×5×2×7√5×4
=210√20
Similar questions