Physics, asked by sarojinisurendran121, 9 months ago

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Answered by shadowsabers03
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\dfrac {\Delta Z}{Z}=4\cdot\dfrac {\Delta A}{A}+\dfrac {1}{3}\cdot\dfrac{\Delta B}{B}+\dfrac{\Delta C}{C}+\dfrac {3}{2}\cdot\dfrac {\Delta D}{D}\\\\\\\dfrac{\Delta Z}{Z}=\dfrac {4\Delta A}{A}+\dfrac{\Delta B}{3B}+\dfrac {\Delta C}{C}+\dfrac {3\Delta D}{2D}

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