Question

please answer this question ​

Answer 1

To find :-

The value of y =?

Answer:

$= > 2y - \frac{1}{2} = y - \frac{1}{2}$

$= > \frac{4y - 1}{2} = \frac{2y - 1}{2}$

Denominator is same so gets cancelled,

$= > 4y - 1 = 2y - 1 \\ = > 4y - 2y = - 1 + 1 = 0 \\ = > 2y = 0 \\ = > y = 0$

Therefore the value of y is 0.