please answer this question
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cos(A+B) = 0
Step-by-step explanation:
ABC is a right angled triangle,
So, A+B+C = 180
=> A+B = 180-C
=> A+B = 180-(90) ( Since C=90 )
=> A+B = 90
Now, cos(A+B) => cos(90) = 0 ( Since A+B=90 )
Therefore, cos(A+B) = 0.
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