Question

please answer this question ​

Answer 1

Answer:

Integration of 1/x-3 is

log(x-3). Because it is in the form of integration of f'(x) /f(x). =log f(x)

Limits given 4---)8

Apply limits we get,

log(8-3)-log(4-3)

log5-log1

=log5. Log1=0