Math, asked by kailashkhandor, 8 months ago

please answer this question​

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Answered by Anonymous
1

Answer: Q-1 =

Step-by-step explanation:

Sol. 1-(1) circumference of a circle is \pid so

\pid= 1232  ,

22/7×d = 1232

d= 1232×7/22

→d= 392 cm

→r= 196 cm

Sol.1- (2) d= 1.4 m

circumference = \pid

c = 22/7×1.4

c = 44 m

r= 0.7 m

Sol-2 d= 70 cm  = .7 m

1 round = circumference =  \pid

\pid = 22/7 ×.7 =2.2 m

no. of rotations = total distance / circumference

no. = 22 km = 22000 m/2.2 m

→no. = 10000

Sol-3 ⇒  major sector = PRQO , major angle = 300°

            minor sector = PSQO , minor angle = 60°

 

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