Question

please answer this question...​

Answer 1

4x^2-4x-8

4x^2-8x+4x-8

4x(x-2)+4(x-2)

4x+4=0. x-2=0

x=-4/4. x=2

x=-1. x=2

-1,2 are the zeroes of the Quadratic polynomial 4x^2-4x-8

Relationship between zeroes and coefficients

Sum of zeroes=-(coefficient of x)/coefficient of x^2=-(-4)/4=4/4=1

Product of zeroes=constant term/coefficient of x ^2=-8/4=-2

I hope it's help you

Plz mark my answer as a brainliest answer

Answer 2

Answer:

please check this one also