Question

please answer this question​

Answer 1

Solution :-

we have

→   2 sin²A = cos 60° + sin²45°

since, cos 60°= 1/2  and  sin 45° = 1 /√2

→   2 sin²A = (1 / 2 )  + ( 1 / √2)²

→  2 sin² A = (1 / 2 ) + ( 1 / 2 )

→ 2 sin²A = 2 / 2

→ 2 sin² A = 1

→ sin² A = 1 / 2

→ cosec²A = 2      ( Ans.)