Math, asked by renukri7764, 6 months ago

please answer this question

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Answered by rsagnik437
10

x +  \frac{1}{x}  =  \sqrt{3}

By cubing both the sides,in the above equation,we get----

( {x} +  \frac{1}{x} )^{3}  =  ({ \sqrt{3} )}^{3}

 {x}^{3}  +  \frac{1}{ {x}^{3} }  + 3(x +  \frac{1}{x} ) = 3 \sqrt{3}

 {x}^{3} +  \frac{1}{ {x}^{3} } + 3 \sqrt{3} = 3 \sqrt{3}

 {x}^{3}  +  \frac{1}{ {x}^{3} }  = 3 \sqrt{3}  - 3 \sqrt{3}

 {x}^{3}  +  \frac{1}{ {x}^{3} }  = 0

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