Question

Please answer this question

Answer 1

Answer:

option b is right

TO FIND:

the maximum speed, V

KEY POINTS:

• the given graph is acceleration time graph.

• area under acceleration time graph gives change in velocity of the particle.

• the change in velocity will be area of the triangle.

• area of triangle =(1/2)bh

where b is the base and h is height.

• here base represents time, and height represents acceleration.

POINT TO NOTICE:

• at t=0 sec, acceleration , a is 10 m/s^2. there velocity is maximum.

• at t=11 s ,the acceleration , a is zero. so the velocity is zero.

SOLUTION:

CHANGE IN VELOCITY = AREA OF GRAPH =AREA OF TRIANGLE

= (1/2)bh

= (1/2)ta

=(1/2)×11×10

=(11×10)/2

=110/2

V=55 m/s

here change in velocity will be equal to maximum velocity because ,the final velocity is zero.

THE MAXIMUM VELOCITY IS 55 m/s