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Answered by AlluringNightingale
2

Answer :

6) x⁴y⁴(y² + x²)(y + x)(y - x)

7•a) a = -5/2

b) x + y = -1

6) Solution :

=> (x^4)(y^8) - (x^8)(y^4)

=> x⁴y⁴(y⁴ - x⁴)

=> x⁴y⁴(y² + x²)(y² - x²)

=> x⁴y⁴(y² + x²)(y + x)(y - x)

7) Solution :

Part (a) :

Here ,

It is given that , the point (4,-2) lies on the graph of the equation 2x = ay + 3 .

Thus ,

The coordinates of the point (4,-2) must satisfy the given equation .

Thus ,

Putting x = 4 and y = -2 in the given equation , we have ;

=> 2x = ay + 3

=> 2•4 = a•(-2) + 3

=> 8 = -2a + 3

=> 2a = 3 - 8

=> 2a = -5

=> a = -5/2

Part (b) :

→ Note : Infinitely many lines pass through a distinct point .

Here ,

The given point is (2,-3) .

There are infinitely many equations of lines passing through the point (2,-3) and we may choose any of them .

Some of equations of lines passing through the point (2,-3) are :

• x + y = -1

• -x + y = -5

• 3x + 2y = 0

• 2x + y = 1

• 3x + y = 3

.

.

.

and so on .

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