Question

please answer this question....​

Answer 1

Mass of Boron = 0.069 g ( given )

Mass of oxygen = 0.144 g ( given)

Total mass of sample = 0.24 g

percentage of boron = 0.069 / 0.24 * 100 = 40 %

percentage of oxygen = 0.144 / 0.24 * 100 = 60%

HOPE IT HELPS U...

Answer 2

No I am A boy but I am A well behaved boy....

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