please answer this question
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answer for the given problem is given
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Answer:
angle APM=Angle BPQ (Vertically oppositeangle)
angle BOQ+DQP=180
6x+35+4x+15=180
10x+50=180
10x=180-50
x=130/10
x=13
6x+35
6×13+35
78+35
113 degree
angle BPQ = 113 degree
angle DQP = 4x+15=4*13+15=52+15=67 degrees
angle APM = angle PQC (alternate exterior angle)
all the angles are
BPQ=113 degrees
PQD=63degrees
PQC=113 degrees
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